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An industrial worker accidentally inhaled a radioisotope with an activity of 0.200 kBq. The substance swallowed has a very long...Asked by Anonymous
An industrial worker accidentally inhaled a radioisotope with an activity of 0.200 kBq. The substance swallowed has a very long effective half-life and therefore the activity will not change significantly during the workers lifetime. Every decay of the isotope releases 1.12 x 10-14 J of energy into the body and the radioisotope is not eliminated from the body.
Determine the amount of energy absorbed in one year by the worker from this substance
Determine the amount of energy absorbed in one year by the worker from this substance
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Answered by
drwls
200 kBq of activity is equivalent to 200*10^3 radioactive decays per second. This rate can be assumed to be constant. In one year, there will be
(200*10^3 decays/s)*3600*24*365 s/yr) = 6.3*10^12 decays. Multiply this by 1.12*10^-14 J/decay for total Joules absorbed per year.
(200*10^3 decays/s)*3600*24*365 s/yr) = 6.3*10^12 decays. Multiply this by 1.12*10^-14 J/decay for total Joules absorbed per year.
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