An in-ground swimming pool has the dimensions 20 m x 15 m. It is filled with water to a uniform depth of 3.00 m.What is the total force exerted on the bottom of the swimming pool?The density of water = 1.00 × 103 kg/m3.

Answer 1

consider a column of water 1cm^3 with a height of 300cm. It's weight will be
mass=300g
weight=.3*9.8 Newtons
force at bottom=that weight
total force on bottom of pool=force*area
-.3x9.8x20x15 Newtons

Answer 2

Is there any Answer With this?