To find angle \( b \) using the properties of exterior angles of triangles, we can use the fact that the exterior angle is equal to the sum of the two opposite interior angles.
Given:
- The exterior angle at angle \( a \) is \( 142° \).
- The two interior angles are \( a \) and \( b \).
Using the property of exterior angles: \[ \text{Exterior Angle} = a + b \] We can set up the equation: \[ 142° = a + b \]
Since we also know that in a right triangle, one of the angles is \( 90° \). Therefore, we can express angle \( a \) in terms of \( b \): \[ a = 90° - b \]
Substituting \( a \) into the exterior angle equation: \[ 142° = (90° - b) + b \] This simplifies to: \[ 142° = 90° \]
To isolate \( b \), we rearrange: \[ b = 142° - 90° \] Calculating this gives: \[ b = 52° \]
Therefore, angle \( b \) is \( 52° \).
The correct response is: 52°.