An illustration shows a polygon where the top, right, and bottom sides are perpendicular to each other. A smaller rectangular piece is missing from the center of the left side of the polygon inward. The dimensions are as follows: the top side is 6, the right side is 8, and the bottom side is 6. The left side is divided into three parts. It shows a vertical width of 2 from the top Solve the following problem using what you know about composite figures. What is the area of the figure?(1 point)Responses24 square units24 square units48 square units48 square units30 square units30 square units36 square units36 square units

Answer 1

To find the area of the figure, we need to find the area of the polygon and subtract the area of the missing rectangular piece.

The area of the polygon is the sum of the areas of its individual rectangles. In this case, the polygon is made up of four rectangles.

The top rectangle has a length of 6 and a width of 2, so its area is 6 * 2 = 12 square units.
The right rectangle has a length of 2 (since it is the height of the missing rectangular piece) and a width of 8, so its area is 2 * 8 = 16 square units.
The bottom rectangle has a length of 6 and a width of 2, so its area is 6 * 2 = 12 square units.
Finally, the left rectangle (excluding the missing piece) has a length of 6 and a width of 2, so its area is 6 * 2 = 12 square units.

Therefore, the total area of the polygon is 12 + 16 + 12 + 12 = 52 square units.

Next, we need to find the area of the missing rectangular piece. It has a length of 6 (the same as the left side of the polygon) and a width of 2, so its area is 6 * 2 = 12 square units.

Finally, to find the area of the figure, we subtract the area of the missing piece from the total area of the polygon: 52 - 12 = 40 square units.

Therefore, the correct answer is 40 square units.