An illustration shows a horizontal rectangle of unknown height (in feet) with a circle of diameter 9 feet attached to its top left and a circle of diameter 9 feet attached to its bottom right.

Question

the surface area of the net diagram of the right circular cylinder is 522.81 feet^2. find the height of the curved surface. Use 3.14 for π.

__ feet

pls get the right answer

Answer 1

To find the height of the curved surface of the right circular cylinder, we first need to find the radius of the cylindrical part.

The diameter of the circles is 9 feet, so the radius is half of that, which is 4.5 feet.

The formula for the surface area of a right circular cylinder is:
S = 2πrh

Given that the total surface area is 522.81 feet^2, and the two circles have areas of 2*(π*(4.5)^2), we can subtract that from the total to get the surface area of the curved part:
522.81 - 2*(3.14*(4.5)^2) = 298.71

Plugging this back into the formula and solving for h:
298.71 = 2*(3.14)*(4.5)*h
298.71 = 28.26h
h = 10.56 feet

Therefore, the height of the curved surface of the right circular cylinder is 10.56 feet.