Question

An illustration shows a coordinate plane. Both x- and y-axes range from negative 10 to 10 in one unit increments. A quadrilateral with vertices P Q R S is drawn on it. Vertex P is at coordinates left parenthesis 4 comma 6 right parenthesis, vertex Q is at coordinates left parenthesis 7 comma 2 right parenthesis, vertex R is at coordinates left parenthesis 5 comma negative 2 right parenthesis, and vertex S is at coordinates left parenthesis 2 comma 2 right parenthesis.If figure PQRSis translated 6 units up and 4 units to the left, what are the coordinates of point S′?(1 point)()

Answer 1

To find the new coordinates of point S after the translation, we need to translate it 6 units up and 4 units to the left.

The original coordinates of point S are (2, 2).

1. **Translate 4 units to the left**:
- This affects the x-coordinate:
\[
x' = 2 - 4 = -2
\]

2. **Translate 6 units up**:
- This affects the y-coordinate:
\[
y' = 2 + 6 = 8
\]

So, the coordinates of point \( S' \) after the translation are \((-2, 8)\).