(a) Work out = Wout
= Integral of P dV = nRT/V *dV
= nRT*ln(V2/V1)
The initial pressure and ideal gas law will tell you what n is
(b) Qin = Wout , since the internal enery (and T) do not change
An ideal monatomic gas expands isothermally from 0.590 m3 to 1.25 m3 at a constant temperature of 670 K. If the initial pressure is 8.00 104 Pa.
(a) Find the work done on the gas.
Answer is in J
(b) Find the thermal energy transfer Q.
Answer is in J
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