Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
An ideal gas is sealed within a container at a temperature of 17°C and a pressure of 101 kPa. The container is heated until the...Asked by Buma
An ideal gas is sealed within a container at a temperature of 17°C and a pressure of 101 kPa. The container is heated until the temperature of the gas reaches100°C. A valve in the container is then opened to allow gas to escape until the pressure falls back to 101 kPa at 100°C.
a) Calculate the pressure in the gas just before the valve is opened.
b) Calculate the fraction of the initial mass of gas that was lost as a result of opening the valve
a) Calculate the pressure in the gas just before the valve is opened.
b) Calculate the fraction of the initial mass of gas that was lost as a result of opening the valve
Answers
Answered by
bobpursley
a. P2=T2P1/T1 temps in Kelvins.
b. n1=P1V1/RT1
n2=P2V2/RT2
n2/n2=T1/T2 in kelvins
that is the fraction that remains, so fraction lost is 1- that.
b. n1=P1V1/RT1
n2=P2V2/RT2
n2/n2=T1/T2 in kelvins
that is the fraction that remains, so fraction lost is 1- that.
Answered by
Wudinesh
An ideal gas is sealed in a rigid container at initial temperature of 17 degree and pressure 100kap when it is heated it's temperature reaches 127 degree, the valve is operated. To allow. Gas to escape until the pressure falls back to 100kap at 127 degree. Calculate
Answered by
mekdes
are correct but what about the rest question.?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.