P V = n R T
R = .082 liter atm/(mol deg K)
P = 2.5
V = 1
T = 273+30 = 303
so
2.5 (1) = n *.082 * 300
n = .10162 moles
.10162 * 6.022*10^23 =.612 * 10^23
= 6.12 * 10^22
about 6*10^22
An ideal gas has a pressure of 2.5 atm, a volume of 1.0 L at a temperature of 30.°C. How many molecules are there in the gas?
6.1 × 1023
6.0 × 1022
2.4 × 1022
2.3 × 1023
1 answer