An iceberg has specific weight of 9000 N/m^3 in n ocean, which has a specific weight of 1000 N/m^3. Above the water surface, it was observed that a volume of 2800 m^3 of the iceberg protruded. Determine the volume of the iceberg below the free surface of the ocean.

Answer 1

something is really wrong with your numbers.

Answer 2

Given:
Di = 9000N/m^3 = Density of iceberg.
Dw = 10,000N/m^3? = Density of sea water.
Va = 2800m^3 = Vol. above surface.

Vb=(Di/Dw)*V=V-2800=Vol. below surface.
(9000/10000)*V = V-2800,
V = 28000 m^3 = Vol. of iceberg.

Vb = 28000-2800 = 25,200 M^2 Below surface.

Answer 3

Correction: Vb = 28,000-2800 = 25,200m^3 = Vol. below surface.