The sum of the heats gained is zero (water has negative heat gained).
Heat gained ice+heatgainedwater=0
M*Lf+30*cwater*(19.5-45)=0
solve for M. You have to know the heat of fusion, and the specific heat of water, IN THE CORRECT UNITS>
an ice cube at 0 was dropped into 30.0 g of water in a cup at 45.0 C at the instant that all of the ice was melted, the tempature of the water in the cup was 19.5 C. what was the mass of the icecube?
6 answers
0,0095876946kg
that is what i'm trying to figure out to
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a perfect square ice cube measures 3 cm on each side. It has a mass of 24.6g. What is the density of the ice cube?