An ice cream shop currently sells soft-serve ice cream in cones that have a radius of 3 inches and a height of 6 inches. The shop wants to offer a wider cone for their hard-serve ice cream that has the same volume as their existing cone but a wider radius of 4 inches. What will be the height, to the nearest inch, of the new cone?(1 point)

Responses

14 inches
14 inches

18 inches
18 inches

4 inches
4 inches

3 inches

1 answer

To find the height of the new cone with a radius of 4 inches that has the same volume as the existing cone, we first need to calculate the volume of the original cone.

The volume \( V \) of a cone is given by the formula:

\[ V = \frac{1}{3} \pi r^2 h \]

where \( r \) is the radius and \( h \) is the height.

Volume of the Original Cone

For the original cone:

  • Radius (\( r \)) = 3 inches
  • Height (\( h \)) = 6 inches

Calculating the volume:

\[ V = \frac{1}{3} \pi (3^2)(6) = \frac{1}{3} \pi (9)(6) = \frac{1}{3} \pi (54) = 18\pi \text{ cubic inches} \]

Volume of the New Cone

For the new cone, we want it to have the same volume of \( 18\pi \) cubic inches and a radius of 4 inches.

Let the height of the new cone be \( H \). The volume of the new cone can be expressed as:

\[ V = \frac{1}{3} \pi (4^2) H = \frac{1}{3} \pi (16) H = \frac{16}{3} \pi H \]

Setting the Volumes Equal

We set the volume of the new cone equal to the volume of the original cone:

\[ \frac{16}{3} \pi H = 18\pi \]

To eliminate \( \pi \) from both sides, we divide each side by \( \pi \):

\[ \frac{16}{3} H = 18 \]

Solving for \( H \)

Now, we solve for \( H \):

\[ H = 18 \cdot \frac{3}{16} = \frac{54}{16} = \frac{27}{8} \]

Calculating \( \frac{27}{8} \):

\[ \frac{27}{8} = 3.375 \]

Rounding to the Nearest Inch

Since the question asks for the height to the nearest inch, we round \( 3.375 \) to \( 3 \).

Thus, the height of the new cone is:

3 inches