An green hoop with mass mh = 2.4 kg and radius Rh = 0.14 m hangs from a string that goes over a blue solid disk pulley with mass md = 2.2 kg and radius Rd = 0.1 m. The other end of the string is attached to a massless axel through the center of an orange sphere on a flat horizontal surface that rolls without slipping and has mass ms = 3.5 kg and radius Rs = 0.22 m. The system is released from rest.

1)What is magnitude of the linear acceleration of the hoop?

2)What is magnitude of the linear acceleration of the sphere?

3)What is the magnitude of the angular acceleration of the disk pulley?

4)What is the magnitude of the angular acceleration of the sphere?

5)What is the tension in the string between the sphere and disk pulley?

6)What is the tension in the string between the hoop and disk pulley?

7)The green hoop falls a distance d = 1.7 m. (After being released from rest.)How much time does the hoop take to fall 1.7 m?

8)What is the magnitude of the velocity of the green hoop after it has dropped 1.7 m?

9)What is the magnitude of the final angular speed of the orange sphere (after the green hoop has fallen the 1.7 m)?

Someone please help me! I'm so lost!

10 answers

HOW DO YOU DO THIS>>>
1) F=ma
a=(mh*g)/(7/5ms+1/2md+mh)
2) same answer as 1 because it is a system
3)a=alpha*R
alpha=a/Rd (use a from 1)
4) similar to 3
alpha=a/Rs
5)F=ma
T=ms*a
T=7/5ms*a (a from 1)
6)T=mh(g-a)
7)d=1/2at^2 (position formula - starting position and velocity are zero)
t=sqrt(2d/a) (use a from 1)
8)vf^2=vi^2 +2ad (initial velocity = 0)
vf=sqrt(2ad)
9)omega=v/Rs
no you
bro im literally going to end it this is not a joke this is a serious cry for help
Why am I going into a physics field why did I do this to myself
physics makes me bruh
were tf did the guy get 7/5 from, that's the one thing I just have no understanding whatsoever of
Moment of intertia
why is the only force acting on the system is the hoop but the tension is not included?
Y'all got this! Keep up the good work, I need more engineers :)