An expression is shown/

4(34x+3x−2)−2(3x2+1+3x)

Rewrite an equivalent expression with the fewest terms possible

(3 points)
x2
+
x−

11 answers

Let's simplify the expression step by step.

Given expression: \[ 4(34x + 3x - 2) - 2(3x^2 + 1 + 3x) \]

  1. First, distribute the constants inside the parentheses:

    \[ 4(34x) + 4(3x) - 4(2) - 2(3x^2) - 2(1) - 2(3x) \]

    This becomes:

    \[ 136x + 12x - 8 - 6x^2 - 2 - 6x \]

  2. Now, combine like terms:

    \[ -6x^2 + (136x + 12x - 6x) - 8 - 2 \]

    Combine the \(x\) terms:

    \[ -6x^2 + 142x - 10 \]

The simplified form of the expression is:

\[ -6x^2 + 142x - 10 \]

If you need it in the form specified in your question, let me know!

An expression is shown/

4(3/4x+3x−2)−2(3x2+1+3x)

Rewrite an equivalent expression with the fewest terms possible

(3 points)

Let's simplify the given expression step by step:

Given expression: \[ 4\left(\frac{3}{4}x + 3x - 2\right) - 2(3x^2 + 1 + 3x) \]

  1. Distribute the constants inside the parentheses:

    • For the first term: \[ 4\left(\frac{3}{4}x\right) = 3x \] \[ 4(3x) = 12x \] \[ 4(-2) = -8 \] So, the first term becomes: \[ 3x + 12x - 8 = 15x - 8 \]

    • For the second term: \[ -2(3x^2) = -6x^2 \] \[ -2(1) = -2 \] \[ -2(3x) = -6x \] So, the second term becomes: \[ -6x^2 - 6x - 2 \]

  2. Combine the two results: The entire expression now looks like this: \[ (15x - 8) + (-6x^2 - 6x - 2) \]

  3. Combine like terms: \[ -6x^2 + (15x - 6x) + (-8 - 2) \] Which simplifies to: \[ -6x^2 + 9x - 10 \]

Thus, the equivalent expression with the fewest terms possible is: \[ -6x^2 + 9x - 10 \]

An equation is shown.

y−5 = −3(x+6)
(2 points)
The equation rewritten in slope-intercept form is
.

The point
is on the graph of the line.

To rewrite the equation \( y - 5 = -3(x + 6) \) in slope-intercept form (which is \( y = mx + b \)), we'll follow these steps:

  1. Distribute the \(-3\) on the right side:

\[ y - 5 = -3x - 18 \]

  1. Add \(5\) to both sides to isolate \(y\):

\[ y = -3x - 18 + 5 \]

\[ y = -3x - 13 \]

Now, the equation in slope-intercept form is: \[ y = -3x - 13 \]

Identifying a Point on the Graph:

To find a point on the graph of the line, we can choose any value for \(x\) and solve for \(y\).

Let's choose \(x = 0\):

  1. Plug \(x = 0\) into the equation: \[ y = -3(0) - 13 = -13 \]

Thus, the point \((0, -13)\) is on the graph of the line.

Final Answers:

  • The equation in slope-intercept form is: \[ y = -3x - 13 \]

  • The point that is on the graph of the line is: \[ (0, -13) \]

y-5=-3(x+6)
slope intercept
the point

To rewrite the equation \( y - 5 = -3(x + 6) \) in slope-intercept form and find a point on the graph, follow these steps:

Step 1: Rewrite in Slope-Intercept Form

Start with the given equation: \[ y - 5 = -3(x + 6) \]

  1. Distribute the \(-3\): \[ y - 5 = -3x - 18 \]

  2. Add \(5\) to both sides: \[ y = -3x - 18 + 5 \] \[ y = -3x - 13 \]

Slope-Intercept Form

The equation in slope-intercept form is: \[ y = -3x - 13 \]

  • Slope (m): \(-3\)
  • Y-intercept (b): \(-13\)

Step 2: Find a Point on the Graph

We can find a point by substituting a value for \(x\) into the equation.

Let's choose \(x = 0\): \[ y = -3(0) - 13 = -13 \] Thus, one point on the graph is: \[ (0, -13) \]

Summary

  • Slope-Intercept Form: \(y = -3x - 13\)
  • Point on the Graph: \((0, -13)\)
there is no 0,-13

I apologize for the oversight! Let's reassess the equation and calculate a suitable point accurately.

Given the equation:

\[ y - 5 = -3(x + 6) \]

Step 1: Rewrite in Slope-Intercept Form

  1. Distribute the \(-3\):

\[ y - 5 = -3x - 18 \]

  1. Add \(5\) to both sides:

\[ y = -3x - 18 + 5 \]

\[ y = -3x - 13 \]

Slope-Intercept Form

The equation in slope-intercept form is: \[ y = -3x - 13 \]

  • Slope (m): \(-3\)
  • Y-intercept (b): \(-13\)

Step 2: Find a Point on the Graph

Let's find a point by choosing a different value for \(x\).

Let's choose \(x = -6\) (a convenient choice because it simplifies our original equation): \[ y = -3(-6) - 13 \]

Calculating it: \[ y = 18 - 13 = 5 \]

Thus, we have the point: \[ (-6, 5) \]

Summary

  • Slope-Intercept Form: \(y = -3x - 13\)
  • Point on the Graph: \((-6, 5)\)

Thank you for your patience! If you have further questions, feel free to ask!

Complete the statements.

The slope of the line is Response area
The y-intercept is Response area Write this as an ordered pair
An equation of the line in slope-intercept form is Response area
A point on the graph that is NOT the y-intercept is Response area
An equation of the line in point-slope form is Response area


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Let's complete the statements based on the equation we derived earlier, which is:

\[ y = -3x - 13 \]

Completing the Statements

  1. The slope of the line is:
    Response area: \(-3\)

  2. The y-intercept is:
    Response area: \(-13\)
    (This can also be written as the ordered pair (0, -13).)

  3. Write this as an ordered pair:
    Response area: \((0, -13)\)

  4. A point on the graph that is NOT the y-intercept is:
    Response area: \((-6, 5)\)
    (This is the point we found in the previous response.)

  5. An equation of the line in point-slope form is:
    The point-slope form is given by the formula:
    \[ y - y_1 = m(x - x_1) \]
    Using the point \((-6, 5)\) and the slope \(-3\):
    Response area:
    \[ y - 5 = -3(x + 6) \]
    (This is equivalent to the form we started with.)

Summary of Responses

  1. The slope of the line is: -3
  2. The y-intercept is: -13
  3. Write this as an ordered pair: (0, -13)
  4. A point on the graph that is NOT the y-intercept is: (-6, 5)
  5. An equation of the line in point-slope form is: y - 5 = -3(x + 6)

Feel free to ask any further questions!

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