An expression is given.

x, squared, minus, 121x
2
−121

The expression can be written in the form left parenthesis, x, plus, a, right parenthesis, left parenthesis, x, plus, b, right parenthesis(x+a)(x+b) .

What are the values of a,a and bb ?

1 answer

To factor the expression \( x^2 - 121x \), we can start by rearranging it into the form \( x^2 + ax + b \) and then apply factoring techniques.

The given expression is:

\[ x^2 - 121x \]

To factor this, we can first factor out \( x \):

\[ x(x - 121) \]

Since you specifically asked for the factorization in the form \( (x + a)(x + b) \), we can express \( x - 121 \) as \( x + (-121) \). Thus, we rewrite it as:

\[ x(x + (-121)) \]

In this factorization, we can interpret:

  • \( a = 0 \)
  • \( b = -121 \)

So the values of \( a \) and \( b \) are:

\[ a = 0, \quad b = -121 \]

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