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An experimental chamber has a volume of 60 L. How many moles of oxygen gas will be required to fill the chamber at STP?

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PV = nRT

2.7 Moles because
60L/22.4L gives you 2.7 moles
The formula for STP for gasses is: 1mole/22.4L
Therefore, 60Liters(1mole/22.4L)=2.68 moles or 2.7 moles.

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