An experiment involves picking a card from a selection of cards numbered 5, 10, and 15. In equation form, what is the probability model for this experiment? List the values of x in ascending order.(2 points)
f(x)=___, where x=___, ___, ___
5 answers
f(x) = 1/3, where x = 5, 10, 15
If the table below represents a probability model based on observed frequencies, what is the value of x ?
Y C A R E S
P(Y) 0.25 0.18 0.30 0.17 x (1 point)
Responses
1
1
0.01
0.01
0.20
0.20
0.10
Y C A R E S
P(Y) 0.25 0.18 0.30 0.17 x (1 point)
Responses
1
1
0.01
0.01
0.20
0.20
0.10
The sum of the probabilities should be equal to 1. Given the information provided, we can calculate the value of x by subtracting the sum of the given probabilities from 1.
Sum of given probabilities = 0.25 + 0.18 + 0.30 + 0.17 = 0.90
x = 1 - 0.90 = 0.10
Therefore, the value of x is 0.10.
Sum of given probabilities = 0.25 + 0.18 + 0.30 + 0.17 = 0.90
x = 1 - 0.90 = 0.10
Therefore, the value of x is 0.10.
Use the table to answer the question.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
(1 point)
Responses
300
300
100
100
50
50
200
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
(1 point)
Responses
300
300
100
100
50
50
200
To estimate the expected number of white balls in Bowl B, we can use the proportion of white balls in Bowl A:
Number of white balls in Bowl A = 45
Total number of balls in Bowl A = 45 + 55 = 100
Proportion of white balls in Bowl A = 45/100 = 0.45
If Bowl B contains 500 balls, then the estimated number of white balls in Bowl B would be:
Number of white balls in Bowl B = 0.45 * 500 = 225
Similarly, the estimated number of red balls in Bowl B would be:
Number of red balls in Bowl B = 500 - 225 = 275
The estimated difference in the expected number of white and red balls in Bowl B is:
Difference = Number of white balls in Bowl B - Number of red balls in Bowl B
Difference = 225 - 275
Difference = -50
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 50 (Note that it is negative which means there are fewer white balls expected than red balls in Bowl B).
Number of white balls in Bowl A = 45
Total number of balls in Bowl A = 45 + 55 = 100
Proportion of white balls in Bowl A = 45/100 = 0.45
If Bowl B contains 500 balls, then the estimated number of white balls in Bowl B would be:
Number of white balls in Bowl B = 0.45 * 500 = 225
Similarly, the estimated number of red balls in Bowl B would be:
Number of red balls in Bowl B = 500 - 225 = 275
The estimated difference in the expected number of white and red balls in Bowl B is:
Difference = Number of white balls in Bowl B - Number of red balls in Bowl B
Difference = 225 - 275
Difference = -50
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 50 (Note that it is negative which means there are fewer white balls expected than red balls in Bowl B).