Asked by probability
An experiment has two possible outcomes A or B. The probability that A will occur is. You are going to perform this experiment eight times. What is the probability that B will occur at least three times?
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Answered by
probability
An experiment has two possible outcomes A or B. The probability that A will occur is 1/3. You are going to perform this experiment eight times. What is the probability that B will occur at least three times?
Answered by
R_scott
this is a binomial relationship
(A + B)^8 ... (1/3 + 2/3)^8
three times means ... NOT 0, 1, or 2
p(B ≥ 3) = 1 - {[(1/3)^8 + [8 * (1/3)^7 * (2/3)] + [28 * (1/3)^6 * (2/3)^2]}
(A + B)^8 ... (1/3 + 2/3)^8
three times means ... NOT 0, 1, or 2
p(B ≥ 3) = 1 - {[(1/3)^8 + [8 * (1/3)^7 * (2/3)] + [28 * (1/3)^6 * (2/3)^2]}
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