P(A) + P(B) + P(C) = 1 = 5P(A)
P(A) = P(B) = 1/5
P(C) = 2/5
An experiment has three possible outcomes: A, B,and C. If P(A)=P(B) and P(C)=2P(A) what is the probability of each event
3 answers
I don't know how drwls got 5P(A).
P(A) + P(B) + P(C) = 1
P(A) + P(A) + 2P(A) = 1 = 4P(A)
P(A) = 1/4 = P(B)
P(C) = 2P(A) = 1/2
P(A) + P(B) + P(C) = 1
P(A) + P(A) + 2P(A) = 1 = 4P(A)
P(A) = 1/4 = P(B)
P(C) = 2P(A) = 1/2
Yes, my mistake.