An examination is normally distributed with a mean score of 77 and a deviation of 6. find the percent of individuals scoring as indicated below:

Question

between 71-83
between 83-65
above 89
less than 65
between 77 and 65

Answer 1

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportions/probabilities related to the Z scores.