An event in the Summer Olympics is 10-meter springboard diving. In this event, the height s, in meters, of a diver above the water t seconds after jumping is given by s(t) = –4.9t2 + 7.1t + 10. What is the maximum height that the diver will be above the water? Round to the nearest tenth

M= __________

1 answer

Since you labeled it "college" algebra, I will assume you know Calculus

s(t) = -4.9t^2 + 7.1t + 10
v(t) = -9.8t + 7.1
= 0 for a max of s(t)

9.8t = 7.1
t = 71/98

s(71/98) = -4.9*71/98)^2 + 7.1(71/98) + 10
= appr 12.58 m

or 12.6 m above water (to the nearest tenth)
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