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an equivalent representation of the definite integral of 3 to 1 2xcos(x^2)dx is
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Let u = x^2
then we have integral from 9 to 1 of cos(u) du
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Starting with F(x) = integral (-2, x) 3t^2(cos (t^3) + 2) dt, use substitution u(t)=t^3 to rewrite the definite integral. You
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consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign)
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consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign)
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consider the function f that is continuous on the interval [-5,5] and for which the definite integral 0(bottom of integral sign)
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