Asked by Tyler
An equilibrium mixture at 852 K is found to contain 3.61*10^-3 mol/L of SO2, 6.11*10^-4 mol/L of O2, and 1.01*10^-2 mol/L of SO3. Calculate the equilibrium constant Keq, for the reaction where SO2 and O2 are reactants and SO3 is the product.
Equation would be:
2SO2 + O2 <---> 2SO3
so the equilibrium equation would be:
Keq= [1.01*10^-2]^2/[3.61*10^-3]^2[6.11*10^-4]
but what do I do with the 852 K, will it change the answer at the end after I find the Keq, poor does it change the numbers now?
Equation would be:
2SO2 + O2 <---> 2SO3
so the equilibrium equation would be:
Keq= [1.01*10^-2]^2/[3.61*10^-3]^2[6.11*10^-4]
but what do I do with the 852 K, will it change the answer at the end after I find the Keq, poor does it change the numbers now?
Answers
Answered by
DrBob222
You work this EXACTLY as you did for the previous problem. The 852 never enters into it EXCEPT that the Keq you calculate will be good ONLY for that temperature.
Answered by
Tyler
So basically, the temperature is there just to be there?
Answered by
DrBob222
In the problem, yes. In real day to day work, you must know the temperature for which the K is given because K is different at some other temperature.
Answered by
Tyler
So the answer would be 12811.12?
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