An equilibrium mixture at 225∘C contains 8.0×10−2M NH3 and 0.20M H2 for the reaction

Question

3H2(g)+N2(g)←→2NH3(g)

If the Kc at this temperature is 1.7×102, what is the equilibrium concentration of N2?

Answer 1

Kc = [NH3]^2 / [N2] [H2]^3

so [N2] = [NH3]^2 / [H2]^3 Kc