Looks ok to me. It might be easier to read
π/6 + nπ
5π/6 + nπ
So, plug in various values of n to get all the solutions in [0,2π)
There will be four of them
An equation is given. (Enter your answers as a comma-separated list. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
2 cos 2θ − 1 = 0
a). Find all solutions of the equations
answer--> θ= (π+6nπ)/6 , (5π+6nπ)/6
b). Find the solutions in then interval [0,2π).
θ=___________
1 answer