An enzyme has velocities of 0.11 nmol/min at a substrate concentration of 1 μM, 0.34 nmol/min at a substrate concentration of 5 μM, and 0.45 nmol/min at a substrate concentration of 10 μM. What is the Vmax for the enzyme if the KM is 5 × 10–6 M?

Question

An enzyme has velocities of 0.11 nmol/min at a substrate concentration of 1 μM, 0.34 nmol/min at a substrate concentration of 5 μM, and 0.45 nmol/min at a substrate concentration of 10 μM. What is the Vmax for the enzyme if the KM is 5 × 10–6 M?
	A.	
0.22 nmol/min
	B.	
0.68 nmol/min
	C.	
0.90 nmol/min
	D.	
1.12 nmol/min
	E.	
None of the answers is correct.

bobpursley · Answer

By definition, 2*.34 nmol/min

Anonymous · Answer

So the answer would be none of the above? I had gotten C?

Anonymous · Answer

Sorry I just realized what you meant. It's 2 times .34 which equals .68