do this with relative velocity
distance apart=-distancepassenger covers+200
distance apart= (25 -speed passenger)*time +200
distance= 25t - 15t + 1/2 .1 t^2 + 200
ok, solve for t when distance=0. If there is a solution, a collision occurs
An engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200m ahead on the same track. The freight train is traveling at 15.0 m/s in the same direction as the passenger train. The engineer of the passenger train immediately applies the brakes, causing a constant accelaration of -0.100 m/s2, while the freight train continues with constant speed. Take x=0 at the location of the front of the passenger train when the engineer applies the brake.
(a) will the cows nearby witness a collision?
(b) if so, where it take place?
(c) on a single graph, sketch the positions of the frong of the passenger train and the back of the freight train.
1 answer
1 answer