d = 200 - Vo*T = 200 - 28*0.21 = 194 m. = Required stopping distance.
V^2 = Vo^2 + 2a*d = 0,
28^2 + 2a*194 = 0,
388a = -784,
a = -
An engineer in a locomotive sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 200 m from the crossing
and its speed is 28 m/s.
If the engineer’s reaction time is 0.21 s,
what should be the magnitude of the minimum deceleration to avoid an accident?
Answer in units of m/s^2
Please help :)
1 answer
0 answers