ideal efficiency=(385-200)/385
total work out possible=idealefficiency(260+210)
how much more work?=totalworkoutPossible-260
An engine removes 260 J from a reservoir at 385 K and exhausts 210 J to a reservoir at 200 K.
How much more work could be done if the engine were an ideal (Carnot) reversible engine?
I already found the efficiency which is 19.2%
1 answer
1 answer