an engine pumps of 100 kg of water through a height of 10m in 5 second. Given that the efficiency of engine is 60%. If g=10m/s^2 the power of engine is
5 answers
(A).3.3KW(B).0.33KW(C).3.3KW(D).3.3KW
Power
=mgh/Δt / efficiency
=100kg*10m/s²*10m/5s / 60%
= 2000/0.6
= 3333 W
= 3.33 KW
Thank you for posting the answers, but there are too many decimal points that I cannot make anything out of them. In addition, (C) and (D) seem identical to me.
=mgh/Δt / efficiency
=100kg*10m/s²*10m/5s / 60%
= 2000/0.6
= 3333 W
= 3.33 KW
Thank you for posting the answers, but there are too many decimal points that I cannot make anything out of them. In addition, (C) and (D) seem identical to me.
POWER
= mgh/t/efficiency
= 100*10*10/5/60
= 2000/0.6
= 3333 w
= 3.33 kw
= mgh/t/efficiency
= 100*10*10/5/60
= 2000/0.6
= 3333 w
= 3.33 kw
5245485
WRONG
4 answers