An empty 276.0 mL glass bulb weighs 12963.75 cg. The bulb is filled with an unknown gas and now weighs 1.300318∗10-1 Kg. Calculate the density of the gas in g/L and express it with the correct number of significant digits.

Answer 1

1.300318∗10-1 Kg = 130.0318 g = mass bulb + gas
-12963.75 cg. =.........-129.6375 g = mass bulb
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mass gas = ......................? grams
volume = 276.0 mL = 0.2760 L
density = g/L = 0.xxxx/0.2760 = ? 1.4xx
You have 4 s.f. in grams and 4 s.f. in volume so 4 are allowed in the answers.

Answer 2

Thank you! This was super helpful. :)