an employment information service reports that the mean annual salary for full time male workers ages 25 to 34 with a bachelor's degree is $48718. in a random sample of 12 full time males workers ages 25 to 34 with a bachelor's degree, the mean annual salary is $47164 and the standard deviation is $6500.can you reject the service's claim? use ¦Á =0.05. assume the population is normally distributed.

asked by Ricky

11 years ago

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1 answer

z = (48718-47164)/(6500/sqrt(12))
z = .828
which one test right-tailed, left
-tailed, or tow-tailed.

answered by Kuai

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Question

an employment information service reports that the mean annual salary for full time male workers ages 25 to 34 with a bachelor's degree is $48718. in a random sample of 12 full time males workers ages 25 to 34 with a bachelor's degree, the mean annual salary is $47164 and the standard deviation is $6500.can you reject the service's claim? use ¦Á =0.05. assume the population is normally distributed.

1 answer

z = (48718-47164)/(6500/sqrt(12))
z = .828
which one test right-tailed, left
-tailed, or tow-tailed.

Kuai · Answer

z = (48718-47164)/(6500/sqrt(12)) z = .828 which one test right-tailed, left -tailed, or tow-tailed.