an employer wishes to hire three people from a group of 15 applicants. 8 men and 7 women, all qualified to fill the position. if he selects the three at random. what is the probability. a) all will be men? b) one will be a women?

Answer 1

(a) p = 8/15 * 7/14 * 6/13

This is like choosing items without replacement, right?

Answer 2

or ..

prob(3 are all men) = C(8,3) / C(15,3)
= 56/455
= 8/65 , the same as Steve's

b) prob(one woman, two men)
= C(7,1)*C(8,2)/C(15,3)
= 7*28/455
= 28/65