An elevator in a tall building is allowed to reach a maximum speed of 3.61 m/s going down. What must the tension be in the cable to stop this elevator over a duration of 3 seconds if the elevator has a mass of 1370 kg including occupants?

Answer 1

a = 3.61/3 up

Force down = m g = 1370 (9.81)
Force up = T
so
F up = m (a up)
T - 1370 (9,81) = 1370 (3.61/3)