I would convert 288 pm to cm, then cube that to obtain the volume in cc.
Next, mass = volume x density = ?
Next,
(atoms/unit cell)x molar mass/6.02E23 = mass from previous step.
Solve for molar mass.
Then mols = 208g/molar mass
1 mol contains 6.02E23 atoms; how many atoms in the mols of 208 grams.
An element has a body-centered cubic(bcc) structure with a cell edge of 288pm the density of the element is 7.2g/cm3. How many atoms are present in 208g of element
1 answer
1 answer