"at least $360" means ... ≥ $360
... B.) is eliminated
the solutions (shaded region) is above (greater than) the line
... C.) is eliminated
check the points for A.) and D.) to find the solution
An electronic store makes a profit of $72 for every television sold and $90 for every computer sold. The managers target is to make at least $360 a day on sales from televisions and computers. Let x = the number of televisions sold. Let y = the number of computers sold. Which of the following represents three possible solutions to the problem?
A.) 72x + 90y >= 360
[A graph with points (0,4) and (5,0) as a line. Everything above is shaded]
(5,2) (3,3) and (1,4) are possible solutions
B.) 72x + 90y =< 360
[A graph with points (0,5) and (4,0) as a line. Everything below is shaded]
(4,0) (2,2) and (1,1) are possible solutions
C.) 72x + 90y >= 360
[A graph with points (0,4) and (5,0) as a line. Everything bellow is shaded]
(3,1) (2,2) and (1,0) are possible solutions
D.) 72x + 90y >= 360
[A graph with points (0,5) and (4,0) as a line. Everything above is shaded]
(4,0) (3,3) and (1,4) are possible solutions
I don't even know how to solve this... Please help?
4 answers
the answer is a! the y intercept should be 4
option A
Step-by-step explanation:
Let x be the number of television sold and y be the number of computer sold
An electronics store makes a profit of $72 for every television sold and $90 for every computer sold.
Profit for x television is 72x
Profit of y computer is 90y
Total profit is 72x+90y sales profit is atleast 360
so inequality becomes 72×+90y >360 graph is attached below
(5,2) lies on the shaded part, so (5,2) is our solution
(3,3) lies on the shaded part, so (3,3) is our solution
(1,4) lies on the shaded part, so (1,4) is our solution (4,0) (2,2) (1,1) and (1,0) does not lies on the shaded part
So option A is correct
Step-by-step explanation:
Let x be the number of television sold and y be the number of computer sold
An electronics store makes a profit of $72 for every television sold and $90 for every computer sold.
Profit for x television is 72x
Profit of y computer is 90y
Total profit is 72x+90y sales profit is atleast 360
so inequality becomes 72×+90y >360 graph is attached below
(5,2) lies on the shaded part, so (5,2) is our solution
(3,3) lies on the shaded part, so (3,3) is our solution
(1,4) lies on the shaded part, so (1,4) is our solution (4,0) (2,2) (1,1) and (1,0) does not lies on the shaded part
So option A is correct
Yes, that is correct! The solution is represented by the shaded region above the line in option A. The y-intercept of the line should be (0,4) to indicate that the store needs to sell at least 4 televisions (with profit of $72 each) to make a profit of $360 or more.
1 answer