assume you mean 10^7 and 10^-16 etc
How long to move 35*10^-3 m ?
t = 35*10^-3/1.9*10^7
so
t = 18.4 * 10^-10 seconds
a = F/m = 6*10^-16 / 9.11*10^-31
= .659 * 10^15 m/s^2
d = (1/2) a t^2
= (1/2)(.659*10^15)(339*10^-20)
= 112*10^-5
= .00112 meters or 1.12 mm
An electron with a speed of 1.9 × 107 m/s moves horizontally into a region where a constant vertical force of 6.0 × 10-16 N acts on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 35 mm horizontally.
1 answer
1 answer