An electron with a speed of 1.3 × 107 m/s moves horizontally into a region where a constant vertical force of 4.4 × 10-16 N acts on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.

Answer 1

There is vertical acceleration
ay = F/m = 4.83*10^14 m/s^2

The time it takes to move 29 mm = 0.029 m horizontally is
T = 0.029 m/1.3*10^7s = 2.23*10^-9 s

The vertical distance moved is

Y = (1/2)*ay*T^2 = 2.4*10-3 m = 2.4 mm

Answer 2

its giving me a wrong answear can u check again plz

Answer 3

it is giving me 0.0024m as a wrong answer

Answer 4

THANKS!!!