A.
KE=eU=1.6•10⁻¹⁹•150 =2.4•10⁻¹⁷ J
B.
KE=mv²/2
v=sqrt(2•KE/m)
C.
a= v²/2d
D.
v=at
t=v/a
An electron with a mass of 9.11 *10^31 Kg is accelerated from rest across a set if parallel plates that have a potential difference of 150 v and are separated by 0.80 cm
A) determine the kinetic energy of the electron after it crosses between the plates. (Ans 2.4 * 10-17 )
B) determine the final speed of he electron ( ans 7.3 * 10^6 m/s)
C) determine the acceleration of the electron while it is between the plates. ( ans 3.3 * 10^15 m/s)
D) determine the time required for the electron
to travel across the plates. (Ans 2.2 * 10-9 s)
1 answer