F = Q E = m a
so
1.6*10^-19 * 1.5*10^2 = 9.1*10^-11 * a
solve for a
distance = 10^-2 = (1/2) a t^2
solve for t
An electron, travelling at 2.3*10^ 3 m/s , enters perpendicular to the electric field between two horizontal charged parallel plates. If the electric field strength is 1.5*10^ 2 V/m. , calculate the time taken for the electron to deflect a distance of 1.0 * 10 ^ - 2 * m toward the positive plate. Ignore gravita tional effects.
1 answer
1 answer