dx=(xf-xi)
vx=dx/dt=dx/4E-6
similarlly, vy, vz.
then for the second part, knowing the velocities
xf=xi+vx*dt
An electron passes location
h0.02m, 0.04m,−0.06mi, and 4 μs later is de-
tected at location h0.02 m, 1.84 m,−0.86 mi.
Find the average velocity of the elecron:
¯v = <vx, vy, vz>
If the electron continues to travel at this av-
erage velocity, find where it will be in another
9 μs :
~d = <dx, dy, dz>
Answer in units of m
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