vf - vi = 5*10^6 - 2*10^6 = 3*10^6
where vf is the final speed and vi is the initial speed.
Assuming a constant deceleration, the electron passes through 2.1 multiply 4cm = 8.4 cm of paper.
8.4 = 1/2*a*t^2
deltav = 3*10^6 = a*t
where a is the acceleration, t is the time. You have two equations with two unkowns (a and t). Use algebra to solve for t, the time taken by the electron to pass through the sheet.
An electron moving at a speed of 5 multiply by 10 raise to power six m/s was shot through a sheet of paper which is 2.1 multiply by 4cm thick.the electron emerges from the paper with a speed of 2 multiply by 10 raise to power six m/s,find the time taken by the electron to pass through the sheet.
1 answer