An electron (mass m = 9.11e-31 kg) is accelerated in the uniform field E (E = 2.00e4 N/C) between two parallel charged plates. The separation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.

Question

An electron (mass m = 9.11e-31 kg) is accelerated in the uniform field E (E = 2.00e4 N/C) between two parallel charged plates. The separation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.
What speed does it leave the hole (in m/s)?  I have worked the problem with help from a prior question very similar, but cannot seem to produce a correct answer.  May I see the work, not just the formula?

drwls · Answer

Let's see your work first. We'll tell you where you went wrong. e*E*X is the kinetic energy acquired. Make usre X is in meters. Set the KE equal to (1/2)mV^2 and solve for V.