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An electron is released from rest at a distance of 9 cm from a proton. How fast will the electron be moving when it is 3 cm from the proton?

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At nine cm, the potential V=kq/.09
at three cm, the potential V=kq/.03

energy gained by electron=differencePotential*e

1/2 mv^2=kq(1/.03-1/.09)e

solve for v

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