a. figure energy for the photon, for the given frequency. E=hf
b. then, E= constant(1/n^2-1/16)
figure n
I can check your work if necessary.
An electron in a hydrogen atom relaxes to the n= 4 level, emitting light of 138 THz.
What is the value of n for the level in which the electron originated?
2 answers
3.6912*10^10
2 answers