Mg ==> Mg^+2 + 2e
Au^+3 + 3e ==> Au
3Mg + 2Au^+3 ==> 3Mg^+2 + 2Au
An electrochemical cell is created using gold and magnesium half-cells.
a. Determine which half-cell will undergo oxidation and which will undergo reduction,
identify anode and cathode, and calculate the voltage for the cell. You do not need to
diagram the cell.
b. If the mass of the magnesium electrode changes by 5.0 g, what will be the change in
mass of the gold electrode, and will its mass increase or decrease?
1 answer
3 answers