To find the resistance of the lamp, we can use Ohm's Law which states that the resistance (R) of a circuit is equal to the voltage (V) divided by the current (I), or R = V/I.
In this case, the voltage (V) is given as 240 volts and the power (P) in watts is given as 60 watts. Since power is equal to voltage multiplied by current (P = V * I), we can rearrange the equation to solve for current (I): I = P/V.
Substituting the given values: I = 60 watts / 240 volts = 0.25 A (Amperes).
Now, we can use Ohm's Law to find the resistance (R): R = V/I = 240 volts / 0.25 A = 960 ohms.
Therefore, the resistance of the lamp when operated at the correct voltage is 960 ohms.
An electric lamp is marked 240 volt ,60 watt,what is the resistance when it is operated at the correct voltage
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