An electric heater that produces 860 W (1 W = 1 J/s) of power is used to vaporize water. How much water at 100 0C can be changed to steam in 5 min by the heater? Use Lv = 2.25x106 J/kg for water at 100 0C and express your final answer in grams.

2 answers

masswater/5min=860*5*60/2.25E6 (1000) grams

=115 grams. check all that.
answer please because i really don't know that all thank you