An electric drill starts from rest and rotates with a constant angular acceleration. After the drill has rotated through a certain angle, the magnitude of the centripetal acceleration of a point on the drill is twice the magnitude of the tangential acceleration. What is the angle?

Answer 1

w = a*t where a is the angular acceleration, in rad/s^2, and t is the time since it started to accelerate

R w^2 = R*(a*t)^2 = 2 R*a

R cancels out. a^2* t^2 = 2a

t = sqrt (2/a)

I cannot provide a numerical value without knowing the acceleration rate.