An electric dipole is made of two charges of equal magnitudes and opposite signs. The

positive charge, q = 1.0μC, is located at the point (x, y, z) = (0.00cm, 1.0cm, 0.00cm), while
the negative charge is located at the point (x, y, z) = (0.00cm,−1.0cm, 0.00cm). How much
work will be done by an electric field ~E
= (3.0 × 106N/C)~i
to bring the dipole to its stable
equilibrium position?

1 answer

I think its .06 J